Bash Question

[Ben Kelley]

$? is the exit code of the previous command


On Thu, 14 Oct 2004 15:00:17 -0500, djgoku <djgoku at gmail.com> wrote:
> Hi Everyone,
> 
> I am working on a bash script, and currently looking at examples. I
> came across something I'm not sure what it means: if (( $? )); , the
> double quotes and the $? is what I don't get. In the script there is
> no variable set for ? so kinda lost.
> 
> Possible info: Simply enclose the particular arithmetic expression
> between a "$((" and a "))",
>                      and bash will evaluate the expression.
> 
> And also anyone have recommendation of a good bash scripting book.
> 
> Learning the bash Shell, 2nd Edition?
> 
> Thanks,
> 
> --
> dj_goku
> -www.djgoku.com-
> -www.tektronic.org-
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