So in Raid 5 the parity recovers data as well as identifying if data has 
been corrupted?  There was some equation, years ago that started:
	- 1 bit parity identifies an odd number of bit errors
	- 1 bit parity misses an even number of bit errors
	- 2 bits parity ....  BUT ITS NOT LINEAR, ITS EXP

So what if the partity disk bites it?

Mick Ohrberg wrote:
> Theoretically, providing all the disks are the same size, it's the total sum
> of all disks, minus one disk (the parity disk).
> 
> 	/Mick
> 
> | -----Original Message-----
> | From: owner-kclug@marauder.illiana.net
> | [mailto:owner-kclug@marauder.illiana.net]On Behalf Of Jeremy Fowler
> | Sent: Sunday, September 01, 2002 4:27 PM
> | To: Kclug@Kclug. Org
> | Subject: RAID 5 Equation
> |
> |
> | Anyone know off hand the equation used to find the usable storage space
> | available with RAID 5?
> |
> |